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Peroxides: The peroxides are the compounds containing oxygen-oxygen $$(O-O) $$ single bond or peroxide ion $$ O_2^{2-} $$. The oxidation state of oxygen in peroxides is $$ -1. $$ These are strong oxidising agents e.g. $$ Na_2O_2,H_2O_2 $$ etc.
A peroxide is any compound which has two oxygen atoms bonded together. The O-O group is the peroxide group of the compound. And Hydrogen Peroxide is the simplest peroxide. The chemical formula for hydrogen peroxide is H2O2. It is a water molecule with one extra atom of oxygen, It has various uses ranging from disinfectant to propellant for rockets.
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The stability order of oxide, peroxide and superoxide of alkali metal is normal oxide > peroxide > super oxide. O 2 − Monoxide ion + 1 2 O 2 → O 2 − 2 Peroxide ion O 2 − 2 Peroxide ion + O 2 → 2 (O − 2) Superoxide ion
41. The number of peroxide linkage in CrO5 and H2SO4 respectively are 1,1 2,0 2,1 1,2. View Solution. Q3.
1.propene on reaction with HCL in presence of peroxide gives. 2.also in place of HCL if HI is substituted what is the product formed 3.does hcl and hi react the same as hbr reacts with propene is absence of peroxide 4.does hf give product with propene in presence and absence of peroxide
Assertion :Propene reacts with H B r in the presence of benzoyl peroxide to yield 2-bromopropane. Reason: In presence of peroxide, the addition of H B r to propene follows ionic mechanism. View Solution
In H 2 S O 5, one peroxide bond is present. So, the oxidation number of 2 oxygen atoms is − 2. (Compare hydrogen peroxide, H 2 O 2, 2 atoms of oxygen will get − 1 oxidation number each). The remaining 3 atoms will have − 2 oxidation number each. This is a special case. Oxidation number of each hydrogen atom is + 1 only.
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B a O 2 has peroxide linkage. [ O − − O − ] B a 2 + p e r o x i d e l i n k a g e . In this compound, two oxygen atoms are linked together by a single covalent bond.