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19 lut 2019 · 2. Guava's math libraries offer two methods that are useful when calculating exact integer powers: pow(int b, int k) calculates b to the kth the power, and wraps on overflow. checkedPow(int b, int k) is identical except that it throws ArithmeticException on overflow.
19 gru 2012 · Try using: bmi = weight / Math.pow(height / 100.0, 2.0); Because both height and 100 are integers, you were likely getting the wrong answer when dividing. However, 100.0 is a double. I suggest you make weight a double as well. Also, the ^ operator is not for powers. Use the Math.pow() method instead.
30 wrz 2014 · The formula for the volume of a sphere is V = 4/3 * PI * radius^3 Convert the formula to Java and add a line which calculates and stores the value of volume in an appropriately named variable. Use Math.PI for PI and Math.pow to cube the radius. Print your results to the screen with an appropriate message.
18 lis 2021 · Option 2. private static boolean isNthRoot(int value, int n) {. double a = Math.pow(value, 1.0 / n); return Math.pow(Math.round(a), n) == value; } The advantage of this method is that there is no need to define a precision. However, we need to perform another pow operation so this will affect performance.
2 maj 2015 · Option 1: Cast result of Math.pow to long: public class PowerCalculator{. /**. * Calculate the non-negative power of an integer number. If a negative power is input, the method returns 1. *. * @param number The number to take power. * @param power The power factor to be taken to.
23 kwi 2011 · 12. Additionally for what was said, if you want integer powers of two, then 1 << x (or 1L << x) is a faster way to calculate 2 x than Math.pow(2,x) or a multiplication loop, and is guaranteed to give you an int (or long) result. It only uses the lowest 5 (or 6) bits of x (i.e. x & 31 (or x & 63)), though, shifting between 0 and 31 (or 63) bits.
27 wrz 2010 · The Math.pow function needs two arguments, the base and the power. You are only passing in one value - the product of windSpeed and 16. I think you probably mean:
13 lut 2014 · EDIT: If it is required to have a method that returns a float you can still use the Math.pow and then include your conversion back from double to float and include your own logic for this. double dblResult = Math.pow(x, p); float floatResult = (float)dblResult; // <-- Change to something safe. It may easily overflow.
24 sty 2017 · You can consider Math.pow to be O(1).. There's a few possible implementations, ranging from a CPU assembler instruction (Java doesn't use this) to a stable software implementation based on (for example) the Taylor series expansion over a few terms (though not exactly the Taylor implementation, there's some more specific algorithms).
2 sie 2013 · If a JavaScript engine were to try to compute Math.pow(-823543, 1 / 7) it would first need to convert 1 / 7 to a decimal, so it would really be computing Math.pow(-823543, 0.14285714285714285) which actually has no real answer. In this case, it may have to return NaN since it couldn't find a real number, even though the real answer should be -7.
