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Algebra. Factor x^3-1. Step 1. Rewrite as . Step 2. Since both terms are perfect cubes, factor using the difference of cubesformula, where and . Step 3. Simplify. Tap for more steps... Step 3.1. Multiply by . Step 3.2. One to any power is one.
factor x^3-1. Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals. For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music….
Limits. x→−3lim x2 + 2x − 3x2 − 9. Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.
line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120) \lim _{x\to 0}(x\ln (x)) \int e^x\cos (x)dx
16 kwi 2018 · x^3 -1 = (x-1) (x^2 +x +1) This is a type of factorising called the the sum or difference of two cubes: a^3 - b^3 = (a-b) (a^2+ab +b^2) The sum of cubes is factored as: a^3 + b^3 = (a+b) (a^2-ab +b^2) In this case we have: x^3 -1 so follow the rule above. x^3 -1 = (x-1) (x^2 +x +1)
The solve for x calculator allows you to enter your problem and solve the equation to see the result. Solve in one variable or many.
Solve by Factoring x^3-1=0. x3 − 1 = 0 x 3 - 1 = 0. Rewrite 1 1 as 13 1 3. x3 − 13 = 0 x 3 - 1 3 = 0. Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 + ab+b2) a 3 - b 3 = (a - b) (a 2 + a b + b 2) where a = x a = x and b = 1 b = 1. (x−1)(x2 +x⋅1+12) = 0 (x - 1) (x 2 + x ⋅ 1 + 1 2) = 0. Simplify.
