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  1. If the sample gives off 71.7 cal, it loses energy (as heat), so the value of heat is written as a negative number, −71.7 cal. Substitute the known values into heat = mcΔT and solve for c: −71.7 cal = (10.3 g)( c )(−75.5°C)

  2. 13 gru 2023 · The negative sign associated with PV work done indicates that the system loses energy when the volume increases. If the volume increases at constant pressure (Δ V > 0), the work done by the system is negative, indicating that a system has lost energy by performing work on its surroundings.

  3. Students find the idea of allowing for energy losses by ‘calibrating’ the apparatus with a fuel for which we know the enthalpy change quite demanding. The idea behind this approach is that the same proportion of the total energy transferred is transferred to the water in the calorimeter when different fuels are burnt.

  4. Comparing heat energy from burning alcohols. In this investigation, students use a spirit burner to burn various alcohols while measuring and comparing the amount of heat energy produced. This experiment is suitable for pre-16 students, possibly as an introduction to a topic on fuels.

  5. Based on the Law of Conservation of Energy, the amount of heat energy lost by the hot material equals the amount of heat gained by the cold material. Stated mathematically:

  6. Experiment 6 ∙ Calorimetry 6‐3 Consider what happens when a quantity of hot water is poured into a quantity of cold water inside a calorimeter. The following relationship accounts for the heat exchanged: heat lost by = heat gained by + heat gained by the hot

  7. Energy changes in neutralisation. 2 comments. Bookmark. Study energy changes in two chemical reactions using thermometer strips to measure temperature. Use this class practical to explore energy changes in neutralisation at dropscale.

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