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25 sie 2014 · I am trying to figure out how to perform a 'For Each' loop for each distinct value returned from an SQL query. Here is my pseudo code. connection.ConnectionString = "server=***01\SQLEXPRESS; database=Billing; integrated security=yes" command.Connection = connection command.CommandType = CommandType.Text command.CommandText = "SELECT DISTINCT ...
6 cze 2013 · You can use iif () in a query, you shouldn't need to use VBA. Well yes, if I was just doing this in a small amount, but then going through tons of stats in using a query takes time, especially when I will then go through and do the same thing to multiple sports. So that is highly inefficient.
18 lut 2017 · I need to update a column with an sequential number starting with 1 based on the accountId in the table. How do I do this? so OrderID is NULL to start. so for each row of AccountID I need to updat...
27 lip 2014 · Let see how to run a simple SELECT SQL Query in Excel VBA on an example Excel Worksheet. On the right see my Excel Worksheet and the Message Box with the similar output from my VBA Macro. The VBA Code is below:
2 lut 2024 · Normally, SQL programs have built-in data output interfaces where you can view the results of your queries. However, no one of these data output interfaces will match the level of flexibility and functionality that Excel could deliver. In this tutorial, we will combine the data extraction capability of SQL and the data processing prowess of Excel.
9 wrz 2022 · In a simple words – just write SELECT query as You do in SQL, as string variable. Const COUNTRY_COL_NAME = "Country" Const MAN_PRICE_COL_NAME = "Manufacturing Price" Dim mySQL As String mySQL = "SELECT COUNT([Country]) " & _ "FROM [" & myFile & "].[Sheet1$] " & _ "WHERE [" & MAN_PRICE_COL_NAME & "] > " & manufacturingMinimumPrice & _ " AND ...
14 kwi 2016 · Use a sql statement that returns the ID's as records (and whatever else you'd need, but I'm only seeing a need for id's). - loop over that rs and either refer directly to it to pass rs.Fields("ID") as your criteria or assign rs.Fields("ID") to a variable.
