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1 lut 2010 · UPDATE Table. SET A = '1' IF A > 0 AND A < 1. SET A = '2' IF A > 1 AND A < 2. WHERE A IS NOT NULL; I have seen CASE expression and IF expression in Procedures and Functions but I want to use it in a simple update/select statement.
In this article, we would like to show you UPDATE query with IF condition in MySQL. Quick solution: UPDATE `table_name` SET `column_name` = IF(condition , if_true, if_false); Practical example. To show UPDATE query with IF condition, we will use the following users table:
1) Like the first example, layout your data into columns. 2) Double click into the next blank column beside you’re first row and insert the following formula. = “update table_name set column_value_to_update = ‘” & C2 & “‘ where column_primaryKey = ‘” & A2 & “‘;”.
21 sie 2024 · MySQL IF-THEN-ELSE IF-ELSE Statement: The IF-THEN-ELSEIF-ELSE statement extends conditional logic by allowing multiple conditions to be tested sequentially. If the IF condition is false, the ELSEIF conditions are evaluated one by one.
26 lut 2014 · Here’s a snippet of SQL code and a procedure for updating a MySQL database table using a subquery and data from Microsoft Excel (or similar). Perhaps you could adapt this solution to your own situation.
16 kwi 2016 · For this example, you would have to use the standard logical operators: UPDATE Tests SET TestScore = CASE WHEN (TestId = 10 AND TestSubId = 25) THEN 1000 WHEN (TestId = 11 AND TestSubId = 22) THEN 1100 END, TestScore2 = CASE WHEN (TestId = 10 AND TestSubId = 25) THEN 2000 WHEN (TestId = 11 AND TestSubId = 22) THEN 2100 END WHERE (TestId = 10 ...
6 sty 2022 · SELECT case_id, cat, birth, c_type, CASE -- 1st section: WHEN (COUNT(case_id) OVER (PARTITION BY case_id)) = 1 THEN CASE WHEN (DATEDIFF(NOW(), birth) / 365.25) >= 21 THEN 'SINGLE_PERSON' ELSE 'UNKNOWN' END -- 2nd section: WHEN COUNT(case_id) OVER (PARTITION BY case_id) = 2 AND SUM(CASE WHEN cat = 'WIFE' THEN 1 ELSE 0 END) OVER (PARTITION BY ...
