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27 kwi 2019 · def transpose(A): output = [['']* (len(A)) for y in range(len(A[0]))] # or: output = [['' for x in range(len(A))] for y in range(len(A[0]))] for j in range(len(A[0])): for i in range(len(A)): output[j][i] = A[i][j] return output transpose([[1,2,3],[4,5,6],[7,8,9]])
2 dni temu · Given a matrix of size n X m, find the transpose of the matrix. Transpose of a matrix is obtained by changing rows to columns and columns to rows. In other words, transpose of mat[n][m] is obtained by changing mat[i][j] to mat[j][i]. Example: Follow the given steps to solve the problem:
16 paź 2024 · Transpose of a matrix is obtained by changing rows to columns and columns to rows. In other words, the transpose of A [ ] [ ] is obtained by changing A [i] [j] to A [j] [i]. Example of First Transpose of Matrix. Input: [ [ 1 , 2 , 3 ] , [ 4 , 5 , 6 ] , [ 7 , 8 , 9 ] ] Output: [ [ 1 , 4 , 7 ] , [ 2 , 5 , 8 ] , [ 3 , 6 , 9 ] ]
9 maj 2023 · 1. Define the matrix to be transposed. 2. Use the zip() function to group the corresponding elements of each row together and create tuples from them. 3. Convert each tuple back to a list using a list comprehension. 4. Store the resulting list of lists as the transposed matrix. 5. Print both the original and transposed matrices.
Given a 2D integer array matrix, return the transpose of matrix. The transpose of a matrix is the matrix flipped over its main diagonal, switching the matrix's row and column indices. Example 1: Input: matrix = [[1,2,3],[4,5,6],[7,8,9]] Output: [[1,4,7],[2,5,8],[3,6,9]] Example 2: Input: matrix = [[1,2,3],[4,5,6]] Output: [[1,4],[2,5],[3,6 ...
Implementing the solution for transposing a matrix in Python is quite straightforward thanks to Python's powerful syntax and built-in functions. The provided reference solution uses almost no explicit algorithms because high-level function calls handle the necessary operations.
12 mar 2016 · public static double[][] transposeMatrix(final double[][] matrix) { return IntStream.range(0, matrix[0].length) .mapToObj(i -> Stream.of(matrix).mapToDouble(row -> row[i]).toArray()) .toArray(double[][]::new); }