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  1. 20 lis 2015 · I'm trying to graph a bounce with respect to time. I have these formulas: 1 2mV22 = mgH2 1 2 m V 2 2 = m g H 2. and. H2 = 1 2 V22 g H 2 = 1 2 V 2 2 g. I will have a series of H(t) H (t) formulas as I know how to get the next bounce's initial velocity (last bounce's final velocity * - (coefficient of restitution)).

  2. 9 maj 2015 · I was asked to show that the time interval between the n th and the (n +1)th bounce is t n = (2V/g)* kn/2. This was pretty simple using conservation of energy and motion along straight-line equations. The second question asks me to find the total time T the bouncing ball takes to come to rest. This is where I am stuck.

  3. 22 mar 2015 · Find the total distance traveled, and also the total time, before it comes to rest. What is its average speed? Attempt at solution: Let h h be the initial height of the ball when it is thrown up. Then a distance of 2h 2 h is covered before the first bounce.

  4. y = ax2 + bx + c where y represents the ball’s height at any given time x. Another form of a quadratic equation is y = a(x – h)2 + k where h is the x-coordinate of the vertex, k is the y-coordinate of the vertex, and a is a parameter. This way of writing a quadratic is called the vertex form.

  5. If the ball is caught after its first bounce, determine the resulting displacement response of the mass m. Assume that the collision is perfectly elastic and the system is at rest initially. Data: m = 2 kg, mo = 0.1 kg, k = 100 N/m, c = 5 N-s/m, and h = 2 m. - mo ī h M x(t) k leone Extra credit (20) pts: Determine the time of the second collision.

  6. In this activity, you will record the motion of a bouncing ball using a Motion Detector. You will then analyze the collected data and model the variations in the ball’s height as a function of time during one bounce using both the general and vertex forms of the quadratic equation. Objectives

  7. 11 sie 2021 · Using conservation of momentum requires four basic steps. The first step is crucial: Identify a closed system (total mass is constant, no net external force acts on the system). Write down an expression representing the total momentum of the system before the “event” (explosion or collision).

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