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To calculate the heat energy required to boil 49.05 g of ethanol, you can use the given heat of vaporization and the mass of the ethanol. The calculation will utilize the formula Q = m × ΔHvap, where Q is the heat energy, m is the mass of the substance, and ΔHvap is the heat of vaporization.
- the heat of vaporization for ethanol is 0.826 kj/g 0.826 kj/g ...
For example, if we want to calculate the heat energy...
- the heat of vaporization for ethanol is 0.826 kj/g 0.826 kj/g ...
25 sie 2023 · Explanation: To calculate the heat energy required to boil 66.45 g of ethanol, we use the given value of the heat of vaporization, which is 0.826 kJ/g. The equation for heat energy is q = mass x heat of vaporization.
6 lut 2023 · For example, if we want to calculate the heat energy required to boil 75.25 g of ethanol, we simply multiply the heat of vaporization by the mass of ethanol: 0.826 kJ/g * 75.25 g = 61.05 kJ. So, the heat energy required to boil 75.25 g of ethanol is 61.05 kJ or 61,050 J. To know more about energy.
13 paź 2023 · Calculate the heat energy in joules required to boil 44.75 g of ethanol. heat energy: J. Added by Stephen C. Instant Answer. Step 1. We know that 1 kJ = 1000 J. So, 0.826 kJ/g = 0.826 * 1000 J/g = 826 J/g.
To find the heat energy, we can use the formula: Heat energy (Q) = Mass (m) × Heat of vaporization (L) where Q is the heat energy, m is the mass of ethanol, and L is the heat of vaporization. Now, we can plug in the given values: Q = 54.65 g × 0.826 kJ/g Since we need the answer in joules, we need to convert kJ to J.
Question: The heat of vaporization for ethanol is 0.826 kJ/g. Calculate the heat energy in joules required to boil 60.85 g of ethanol. heat energy: J. Show transcribed image text. There are 2 steps to solve this one.
Convert the heat of vaporization from kilojoules to joules by multiplying 0.826 by 1000. Step 1 To calculate the heat energy required to boil ethanol, we need to use the formula:
