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Final answer: The heat energy required to boil 49.05 g of ethanol is 40,527.3 joules, calculated by multiplying the mass of ethanol with the heat of vaporization and converting kJ to J. Explanation: To calculate the heat energy required to boil 49.05 g of ethanol, you can use the given heat of vaporization and the mass of the ethanol.
12 gru 2020 · Calculate the total heat required (in joules) to convert 3.95 grams liquid ethanol (C2H5OH) at 25.0 °C to gas at 95.0 °C, given that the boiling point of ethanol is 78.5 °C, heat of vaporization is 40.5 kJ/mol, the specific heat of liquid ethanol is 2.45 J/g-K, and the specific heat of gaseous ethanol is 1.43 J/g-K
25 sie 2023 · Explanation: To calculate the heat energy required to boil 66.45 g of ethanol, we use the given value of the heat of vaporization, which is 0.826 kJ/g. The equation for heat energy is q = mass x heat of vaporization.
Question: The heat of vaporization for ethanol is 0.826 kJ/g. Calculate the heat energy in joules required to boil 60.85 g of ethanol. heat energy: J. Show transcribed image text. There are 2 steps to solve this one.
To find the heat energy, we can use the formula: Heat energy (Q) = Mass (m) × Heat of vaporization (L) where Q is the heat energy, m is the mass of ethanol, and L is the heat of vaporization. Now, we can plug in the given values: Q = 54.65 g × 0.826 kJ/g Since we need the answer in joules, we need to convert kJ to J.
VIDEO ANSWER: The heat of Vaporization for Ethanol is zero point 825. Kill the jewel program. We have to calculate the amount of heat and jewels which is needed to boil 27 points. The amount of heat is the same as the amount of vaporization time
Convert the heat of vaporization from kilojoules to joules by multiplying 0.826 by 1000. Step 1 To calculate the heat energy required to boil ethanol, we need to use the formula:
