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You'll get a more accurate result if you compute the difference between the two dates in days and divide by the mean length of a calendar year in days over a 400 year span (365.2425): datediff(day,{start-date},{end-date},) / 365.2425. For instance, select datediff(day,'1 Jan 2000' ,'18 April 2014') / 365.2425.
22 sty 2010 · For MS SQL, you can convert the datetime value to a double value. The integer part contains the number of days since 1900-01-01, the fractional part contains the time in hours. So you can calculate date difference as: cast(date1-date2 as FLOAT)
30 gru 2022 · Transact-SQL reference for the DATEDIFF function. Returns the numerical difference between a start and end date based on datepart.
25 sie 2011 · Return the difference between two date values, in years: SELECT DATEDIFF (year, '2017/08/25', '2011/08/25') AS DateDiff; Try it Yourself » Definition and Usage. The DATEDIFF () function returns the difference between two dates, as an integer. Syntax. DATEDIFF (interval, date1, date2) Parameter Values. Technical Details. More Examples. Example.
To calculate the difference between two dates in years, months, weeks, etc., you use the DATEDIFF() function: DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) ( sql )
23 wrz 2023 · This built-in SQL function allows you to calculate the difference between two datetimes. It’s as simple as DATEDIFF (datepart, startdate, enddate). The datepart could be year, quarter, month, day and so on. SELECT DATEDIFF (day,'2022-01-01','2022-12-31') AS DiffDate.
1 sty 2020 · DATEDIFF() is a basic SQL Server function that can be used to do date math. Specifically, it gets the difference between 2 dates with the results returned in date units specified as years, months days, minutes, seconds as an int (integer) value.
