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I wrote a while loop in a function, but don't know how to stop it. When it doesn't meet its final condition, the loop just go for ever. How can I stop it? def determine_period(universe_array): ...
In Python programming, we use while loops to do a task a certain number of times repeatedly. The while loop checks a condition and executes the task as long as that condition is satisfied. The loop will stop its execution once the condition becomes not satisfied.
There is a much simpler way to use the time condition directly: import time # timeout variable can be omitted, if you use specific value in the while condition timeout = 300 # [seconds] timeout_start = time.time () while time.time () < timeout_start + timeout: test = 0 if test == 5: break test -= 1.
In this tutorial, you'll prepare for future interviews by working through a set of Python practice problems that commonly appear in coding tests. You'll work through the problems yourself and then compare your results with solutions developed by the Real Python team.
1 lis 2012 · 20 Answers. Sorted by: 193. The easiest way is to just interrupt it with the usual Ctrl-C (SIGINT). try: while True: do_something () except KeyboardInterrupt: pass. Since Ctrl-C causes KeyboardInterrupt to be raised, just catch it outside the loop and ignore it. edited Nov 1, 2012 at 16:18. SilentGhost. 318k67310293.
Create a Python while loop program that continuously asks the user for a positive number and keeps a running total. The loop must stop when the user enters a negative number. total = 0 while True: number = float(input("Enter a positive number (or a negative number to stop): ")) if number < 0: break total += number print("Total sum of positive ...
30 wrz 2023 · In this article, we have learned 4 different ways to exit while loops in Python: How to Exit a While Loop in Python with the Control Condition; How to Exit a While Loop in Python with the Break Statement; How to Exit a While Loop in Python with the Return Statement; How to Exit a While Loop in Python by Raising an Exception.