Search results
7 lip 2012 · You have to return JSON error object yourself after setting the StatusCode, like so ... if (BadRequest) { Dictionary<string, object> error = new Dictionary<string, object>(); error.Add("ErrorCode", -1); error.Add("ErrorMessage", "Something really bad happened"); return Json(error); }
I'm looking for the correct way to return JSON with a HTTP status code in my .NET Core Web API controller. I use to use it like this: public IHttpActionResult GetResourceData() {. return this.Content(HttpStatusCode.OK, new { response = "Hello"}); }
17 maj 2023 · Serialize Exceptions Using Newtonsoft.Json. The quickest solution is to use the serialization routines from Newtonsoft.Json library: try { throw new InvalidOperationException("Bad operation"); } catch (Exception ex) { var json = JsonConvert.SerializeObject(ex)!; Assert.NotEmpty(json); }
26 maj 2023 · In this article, you will learn how to allow comments, trailing commas, and quoted numbers in JSON, and how to write numbers as strings. Allow comments and trailing commas. By default, comments and trailing commas are not allowed in JSON.
Error handling lets you catch an error and choose whether to handle it and continue with serialization or let the error bubble up and be thrown in your application. Error handling is defined through two methods: the Error event on JsonSerializer and the OnErrorAttribute. Error Event; OnErrorAttribute
26 maj 2023 · This article shows how to handle overflow JSON with the System.Text.Json namespace. It also shows how to deserialize into JsonElement or JsonNode, as an alternative for other scenarios where the target type might not perfectly match all of the JSON being deserialized.
7 mar 2022 · Shows how to exclude objects with errors while deserializing an array of objects with Newtonsoft. Note: System.Text.Json doesn’t have this functionality
