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22 wrz 2008 · For an expression that returns a true DATE type (SQL Server 2008 and later), see BenR's answer below. SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, @your_date)) for example. SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE())) gives me. 2008-09-22 00:00:00.000 Pros: No varchar<->datetime conversions required; No need to think about locale
10 paź 2011 · In SQL Server 2008 or later, you can easily do this by casting/converting the datetime value to the datatype DATE. A typical example is the following: --Datetime variable declaration DECLARE @dateTimeValue as datetime SET @dateTimeValue=GETDATE() --Cast the datetime value to the DATE datatype SELECT CAST(@dateTimeValue as DATE) as OnlyDate GO
9 sie 2023 · So how do you return or display just the date part of the datetime? For example, 2023-08-09. The Solution. The simplest solution is to use CAST. This code works in SQL Server 2008 and later versions.
1 wrz 2018 · To get the current date and time: And we have a datetime value: 2018-09-01 11:50:05.627. From the datetime value above, you want to extract the date value only and hide the time value. There are several ways to do that: 1. Use CONVERT to VARCHAR: CONVERT syntax: In this case, date only, you we are gonna run this query:
In this SQL Server example, first, we are going to declare a DateTime variable and also use the GETDATE() function. Next, we are going to use the CONVERT, CAST , DATEADD , and DATEPART functions to extract the date part only from a SQL server Datetime Datatype .
10 cze 2007 · Want only the date part in the format (dd-mm-yyyy) stored in table as datetime value which contains date and time.
1 mar 2016 · DECLARE @date datetime = '20160301' SELECT * FROM #Bbb WHERE datetime1 >= @date AND datetime1 < DATEADD(day, 1, @date) ; Or this WHERE clause for dates on a given day or later: WHERE datetime1 >= @date
