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prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120) \lim _{x\to 0}(x\ln (x)) \int e^x\cos (x)dx \int_{0}^{\pi}\sin(x)dx
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Całkowanie. ∫ 01 xe−x2dx. Granice. \lim _ {x \rightarrow-3} \frac {x^ {2}-9} {x^ {2}+2 x-3} x→−3lim x2 + 2x − 3x2 − 9. Rozwiązuj zadania matematyczne, korzystając z naszej bezpłatnej aplikacji, która wyświetla rozwiązania krok po kroku.
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