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23 kwi 2009 · @Alex, the last strcpy(tmp,orig) copies the last part of string to the destination. Eg: replace("abab","a","c") at the end of the loop, result contains, "cbc" and orig points to the last "b" in "abab". The last strcpy appends the "b" so the returned string is "cbcb".
8 maj 2019 · Replacing a substring with another is easy if both substrings have the same length: locate the position of the substring with strstr. if it is present, use memcpy to overwrite it with the new substring. assigning the pointer with *strstr (m, "on") = "in"; is incorrect and should generate a compiler warning.
15 lis 2011 · char *replace_str(char *str, char *orig, char *rep, int start) { static char temp[4096]; static char buffer[4096]; char *p; strcpy(temp, str + start); if(!(p = strstr(temp, orig))) // Is 'orig' even in 'temp'?
1 lis 2023 · For compiling or creating the regular expression regcomp () function is used. It takes three arguments: Syntax: regcomp(®ex, expression, flag) where, regex is a pointer to a memory location where expression is matched and stored. expression is a string type. flag to specify the type of compilation.
5 lip 2021 · And finally, a simple main with a test with multiple occurrences and with original string being a substring of replacement string: int main(void) { char src[] = "!!!asdf!!!asdf!!!asdf!!!asdf!!!"; char orig[] = "asdf"; char new[] = "asdfaaaaaaaaasdf"; puts(replaceAllAndAllocate(src, orig, new)); }
4 lip 2022 · regex_replace() This function is used to replace the pattern matching to the regular expression with a string.
You can replace string by taking reference of the matched group using $. Use the respective matched group number e.g. $1 for first group, $2 for second and so on. The following uses backreference $1, $2, $3, and $4 for the captured groups and add - between each matched group.
