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Use the graph to find the range. Interval Notation: [0, π 2)∪(π 2,π] [0, π 2) ∪ (π 2, π] Set -Builder Notation: {y∣∣0 ≤ y ≤ π,y ≠ π 2} {y | 0 ≤ y ≤ π, y ≠ π 2} Determine the domain and range. Domain: (−∞,−1]∪ [1,∞),{x|x ≤ −1,x ≥ 1} (- ∞, - 1] ∪ [1, ∞), {x | x ≤ - 1, x ≥ 1}
The range of arcsecant: y∈ [0; π/2)∪ ( π/2; π]. Arcsecant is a non-periodic function. The arcsecant increases and is continuous on the interval x∈ (-∞; -1] and x∈ [1, + ∞), since the secant function (x= secy) is strictly increasing and continuous in the intervals [0; π/2) and (π/2;π]
In the following examples, we wish to find in the range of arcsecant such that (a) We may use the relationship between arcsecant and arccosine to rewrite this equation in terms of arccosine.
Suppose $s(x)=\frac{x+2}{x^2+5}$. What is the range of $s$? I know that the range is equivalent to the domain of $s^{-1}(x)$ but that is only true for one-to-one functions.
The range is the set of all valid y y values. Use the graph to find the range. Interval Notation: [0, π 2)∪(π 2,π] [0, π 2) ∪ (π 2, π] Set -Builder Notation: {y∣∣0 ≤ y ≤ π,y ≠ π 2} {y | 0 ≤ y ≤ π, y ≠ π 2}
Learn what rational expressions are and about the values for which they are undefined.
important characteristics. Rational functions arise in many practical and theoretical situations, and are frequently used in . athematics and statistics. The module also introduces the idea of a limit, and shows how this can b. Functions and Hyperbolas. Chapt. r 2 Sketching Hyperbolas. Chapter. lled rational expressions. re A ≠ 0, are known a.
