Search results
liquid or gas can apply a pressure. Pressure Pressure (P) is defined as force (F) divided by the area (A) on which the force is pushing. (See the lesson on Pressure for details.) You can write this as an equation, if you wanted to make some calculations: P = F / A An object can exert downward pressure due to its weight and the force of gravity.
Pressure is the force per unit area that a gas or a liquid exerts on the surface of its con ning volume. Very simply, pressure is the weight per unit area of a uid or a gas P F A (15:1) Pressure is measured in units of Pascals (Pa) where 1 Pa is 1 N/m2.
What determines whether something floats or sinks in a fluid? How can an object sink in one liquid, and yet float in a different liquid? How can a huge ocean liner float, when its mass is so huge, and being made from raw materials that would sink in water? Our study of fluids begins with us addressing questions such as these. 9-1 The Buoyant Force.
Atmospheric pressure at a point is the force per unit area exerted on a small surface containing that point by the weight of air above that surface. In most circumstances atmospheric pressure is closely approximated by the hydrostatic pressure caused by the weight of air above the measurement point.
Pressure. For a static fluid, the only stress is the normal stress since by definition a fluid subjected to a shear stress must deform and undergo motion. Normal stresses are referred to as pressure p. For the general case, the stress on a fluid element or at a point is a tensor ij = stress tensor* = xx xy yx yy zx zy. i = face.
The motions of the particles in a fluid are what produce pressure. For example, when you pump up a bicycle tire, you push air into the tire. Air is made up of tiny particles that are always moving. When air particles bump into the inside surface of the tire, the particles pro-duce a force on the tire.
To define the pressure at a specific point, the pressure is defined as the force dF exerted by a fluid over an infinitesimal element of area dA containing the point, resulting in p = \(\frac{dF}{dA}\).
