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Is there a bug in PowerShell's Start-Process command when accessing the StandardError and StandardOutput properties? If I run the following I get no output: $process = Start-Process -FilePath ping -ArgumentList localhost -NoNewWindow -PassThru -Wait. $process.StandardOutput. $process.StandardError.
25 maj 2022 · Why does Start-Process fail to find the executable (not in the path) if -RedirectStandardOutput or -RedirectStandardError are specified? I.e. [X:\] Start-Process -FilePath "prog.exe" -WorkingDirectory (Get-Location).Path
5 wrz 2019 · I have worked with Start-Process alone, using both -RedirectStandardOutput and -NoNewWindow. The problem is Start-Process doesn't really detach the process.
10 mar 2022 · The Start-Process cmdlet allows you to run one or multiple processes on your computer from within PowerShell. It’s designed to run a process asynchronously or to run an application/script elevated (with administrative privileges).
4 mar 2015 · In a PowerShell window I am executing: Start-Process XXXXX.exe -ArgumentList "some valid arguments" -wait -redirectStandardOutput "D:\\test1.txt" And getting: Start-Process : This command cannot be executed due to the error: The system cannot find the file specified.
25 maj 2022 · By default, Start-Process creates a new process that inherits all the environment variables that are defined in the current process. You can use following command to redirect the output / error to each file.
The Start-Process cmdlet starts one or more processes on the local computer. By default, Start-Process creates a new process that inherits all the environment variables that are defined in the current process.
