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Is there a bug in PowerShell's Start-Process command when accessing the StandardError and StandardOutput properties? If I run the following I get no output: $process = Start-Process -FilePath ping -ArgumentList localhost -NoNewWindow -PassThru -Wait. $process.StandardOutput. $process.StandardError.
5 wrz 2019 · I have worked with Start-Process alone, using both -RedirectStandardOutput and -NoNewWindow. The problem is Start-Process doesn't really detach the process.
25 maj 2022 · Why does Start-Process fail to find the executable (not in the path) if -RedirectStandardOutput or -RedirectStandardError are specified? I.e. [X:\] Start-Process -FilePath "prog.exe" -
10 mar 2022 · The Start-Process cmdlet allows you to run one or multiple processes on your computer from within PowerShell. It’s designed to run a process asynchronously or to run an application/script elevated (with administrative privileges).
3 sie 2017 · You can use Start-Process -PassThru parameter. https://learn.microsoft.com/fr-fr/powershell/module/Microsoft.PowerShell.Management/Start-Process?view=powershell-5.1-PassThru: Returns a process object for each process that the cmdlet started. By default, Start-Process does not generate any output.
Polecenie Start-Process cmdlet uruchamia co najmniej jeden proces na komputerze lokalnym. Domyślnie Start-Process tworzy nowy proces, który dziedziczy wszystkie zmienne środowiskowe zdefiniowane w bieżącym procesie.
The problem with 'Start-Process' is that it does not produce any console output when run remotely using 'Invoke-Command'. I have had to resort to redirecting the output to a file and then reading the file.
