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21 lip 2023 · Step by step video, text & image solution for Solve for x: 1+4+7+10+...+x=287 by Maths experts to help you in doubts & scoring excellent marks in Class 10 exams. 1+4 +7+10 + + x = 590.
How do you solve \displaystyle-{10}+{x}+{4}-{5}={7}{x}-{5} ? https://socratic.org/questions/how-do-you-solve-10-x-4-5-7x-5 First, you gather all the "x" terms on one side of the equation; Explanation: and all of the constants on the other side of the equation.
Given, 1 + 4 + 7 + 10..... + x = 287. We need to find the value of x, First-term, a = 1. Common difference, d = 4-1 = 3. S n = 287. Using the formula, S n = n 2 (2 a + (n − 1) d) 287 = n 2 (2 × 1 + (n-1) 3) 287 = n 2 (2 + 3 n-3) 574 = n (3 n-1) 574 = 3 n 2-n. 3 n 2-n-574 = 0. 3 n 2-42 n + 41 n-574 = 0. 3 n (n-14) + 41 (n-14) = 0 (3 n + 41 ...
17 mar 2020 · Here 1, 4, 7, 10, ... x is an A.P. With first term a = 1 and common difference d = 3. Let there be n terms in the A.P. Then, x = nth term . x = 1 + (n – 1) × 3 = 3n – 2 ...(i) Now, 1 + 4 + 7 + 10 + ... + x = 287. Putting n = 14 in eqn (i), we get . x = 3 × 14 – 2 . x = 40
Solve the equation : 1 + 4 + 7 + 10 +...+ x =287. Solution: Given, the sum of the terms up to x is 287. We have to solve the equation. The sum of the first n terms of an AP is given by. Sₙ = n/2[2a + (n-1)d] Here, first term, a = 1. Common difference, d = 4 - 1 = 3. So, 287 = n/2[2(1) + (n - 1)3] 287 = n/2[2 + 3n - 3] 287 = n/2[3n - 1] 574 ...
If \[\frac{1}{x + 2}, \frac{1}{x + 3}, \frac{1}{x + 5}\] are in A.P. Then, x = Suppose the angles of a triangle are (a − d), a , (a + d) such that , (a + d) >a > (a − d). Write the formula of the sum of first n terms for an A.P.
26 sie 2020 · We have, an = a + (n – 1)d. So, x = 1 + (n – 1) × 3 = 3n – 2. Also, S = n/2 (a + l) So, 287 =n/2 (1+ x) As n cannot be negative, so n = 14. Therefore, x = 3n – 2 = 3 × 14 – 2 = 40.
