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The oscillation time of a pendulum is given by $T = 2\pi\sqrt{\frac{L}{g}}$. With $T = 2$ and $L = 1$ this gives $g = \pi^2$
23 sie 2016 · The equation for half a period in Anedar's answer $$T_{1/2}=\pi \sqrt{\frac{l}{g}}$$ would return the values of $\pi^2$ and $g$ to be equal if one measures a meter long pendulum to complete a half period in 1 second.
25 lis 2011 · The number (Pi)^2, also known as the square of Pi, is a mathematical constant that represents the ratio of a circle's circumference to its diameter. In the context of gravity on earth, (Pi)^2 is used in the formula for calculating the gravitational constant, which is a measure of the strength of gravity on earth.
9 sie 2024 · A wonderful coincidence or an expected connection: why π² ≈ g. Let’s take a brief trip back to our school years and recall some lessons in mathematics and physics. Do you remember what the number π equals? And what is π squared? That’s a strange question too. Of course, it’s 9.87.
8 mar 2013 · What Does Pi Have To Do With Gravity? Let’s start with a quick calculation. You might need your calculator. What is π squared? Does that number look familiar? Does it look like the local...
24 gru 2011 · Pi square is not the figure going out of phase, rather it seems like an absolute ablution through which all other phase variables finds their relativistic and correlation correction of, and finally, from exogenous variation. This is the quest of Planetary motion for its inherent precision.
To address your hypothetical: if Wilkins had defined the meter as the length of a pendulum with three seconds (or a half-period of 1.5 seconds) then g would equal (pi 2)/(1.52). Edit: Grabbed better constants, which improved the accuracy even more.
