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28 lut 2011 · in classes, you can only declare variables that consist of a static value, and not a dynamic value such as "name" . $name. What you would have to do is concat in the constructor, (That's why its there):
I have a [key] => [value] array that return a string when calling a function. my problem is when i concatenate a php variable with array value it gives me this error. Parse error: syntax error, unexpected '$name' (T_VARIABLE) in C:/... My Code: function language( $phrase , $name ) {. static $language= array (. 'hello' => 'Hello '.$name,
As of PHP 8.0, array_combine throws ValueError if the number of elements for each array is not equal; To be on a safer side, you can perform a check instead. $arrayk = array( 'key1', 'key2', 'key3' ); $arrayv = array( 'v1', 'v2', 'v3' ); if ( count( $arrayk ) === count( $arrayv ) ) {.
If an Element is an Array in both Arrays, Arrays are merged recursively, otherwise the element in $ins will overwrite the element in $arr (regardless if key is numeric or not). This also applys to Arrays in $arr, if the Element is scalar in $ins (in difference to the previous approach).
In this PHP 7 tutorial, we are going to learn how to concatenate String, Variable and Arrays in PHP. The concatenate term in PHP refers to joining multiple strings into one string; it also joins variables as well as the arrays. In PHP, concatenation is done by using the concatenation operator (".
Merges the elements of one or more arrays together so that the values of one are appended to the end of the previous one. It returns the resulting array. If the input arrays have the same string keys, then the later value for that key will overwrite the previous one.
You can use the + operator to merge two arrays in a way that the values of the first array never get overwritten, but it does not renumber numeric indexes, so you lose values of arrays that have an index that is also used in the first array.
