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A wide range of past CEMC contests and their solutions to familiarize yourself with the contest format, level of difficulty, and problem solving strategies.
2019 Pascal Contest Solutions Page 2 1. Evaluating, 2 3 + 2 3 = 6 + 6 = 12. Answer: (D) 2. Since a square has four equal sides, the side length of a square equals one-quarter of the perimeter of the square. Thus, the side length of a square with perimeter 28 is 28 4 = 7. Answer: (E) 3. In the diagram, there are 9 hexagons of which 5 are shaded.
Answer: (A) Since \(\frac{1}{3}\) of \(x\) is equal to 4, then \(x\) is equal to \(3 \times 4\) or 12. Thus, \(\frac{1}{6}\) of \(x\) is equal to \(12 \div 6 = 2\). Alternatively, since \(\frac{1}{6}\) is one-half of \(\frac{1}{3}\), then \(\frac{1}{6}\) of \(x\) is equal to one-half of \(\frac{1}{3}\) of \(x\), which is \(4 \div 2\) or 2 ...
Answer: (C) gure are right angles, each line segment is either horizontal or vertical. The height of the gure is 3x and the width of the gure is 2x. This means that the length of the unmarked vertical segment must equal 3x x = 2x. Also, the length of the unmarked horizontal segment must equal 2x x = x.
Past Contests, Solutions and Results. Problems, solutions and results dating back to 1998 can be found in the chart below. For the Gauss, Pascal, Cayley, and Fermat Contests, the CEMC problem set generator can be used to create sets of past problems with customized topics. Gauss. PCF.
The sum of the digits of 26 is 8, which is not a prime number, so the answer is not (E). Since 14 is not a multiple of a three, 14 is not a perfect square, and the sum of the digits of 14 is 1 + 4 = 5 which is prime, then the answer is 14, which is choice (B).
2020PascalContest - Free download as PDF File (.pdf), Text File (.txt) or read online for free.
