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  1. 22 lip 2013 · I don't fully understand nested if statements... for example, if I have two if statements (if 1),( if 2). Also, lets say (if 1) had a nested if statement (if 1-A). When the loop starts, does it stay within (if 1) and (if 1-A) until conditions cause it to go on and only then enters (if 2)?

  2. 12 paź 2023 · For example, let’s create a nested if statement, check the given number, and print a text according to the conditions. Code: long t1 = 11; long t2 = 600; long t3 = 600; void setup() { Serial.begin(9600); } void loop() { if (t1 > 10) { if (t2 < 500) { . Serial.println("Hello"); } else { . Serial.println("World"); } } else if (t3 > 500) { .

  3. 9 paź 2015 · You'll need to make it an array of characters such as char c[140+1];, the size of the longest SMS message + one more for a zero-character string-terminator. C doesn't directly compare strings as simple variables so == and != won't work here.

  4. 28 lis 2019 · Now you can use a for loop to iterate though that list and turn on the LED you want: for (uint8_t i = 0; i < 8; i++) { if (i == value) { digitalWrite(ledPin[i], HIGH); } else { digitalWrite(ledPin[i], LOW); } }

  5. 4 maj 2014 · Hi: I have some nested if and an array comparison. if (readString == "ON1"){ if (SetRoutine ==0){ Contador++; digitalWrite(LED1, HIGH); Memoria[Contador] = 10;} . if (SetRoutine == 1){ Contador++; digitalWrite(LED1, HIGH); Comparador[Contador] = 10; . if(Memoria[1] == Comparador[1]){ <<<<<<=================HERE!!!!!!!!!!!!!!!!!!!

  6. 27 lis 2012 · Typically, rather than nesting the ifs like that, you would do something like this: If ((swcIn > 606) && (swcIn < 609)) {Serial.println ("Vol Dn"); //Yes? Print "Vol Dn" to serial monitor} else if ... There's nothing wrong with a series of else-ifs to check against a set of ranges like that. What is it doing wrong?

  7. 17 wrz 2015 · For instance, you can loop through a C string until you reach the NULL character at the end of the string: for (char *p = str; *p != 0; p++) { ... do something with *p } You can iterate through the entries in a linked list:

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