Search results
1 NaOH + 1 H 2 SO 4 = 1 Na 2 SO 4 (aq) + 1 H 2 O Dla każdego elementu sprawdzamy, czy liczba atomów jest zrównoważona po obu stronach równania. Na nie jest zrównoważony: 1 atomów w odczynnikach i 2 atomów w produktach.
1 H 2 SO 4 (aq) + 2 NaOH = 1 Na 2 SO 4 (s) + 2 H 2 O O is balanced: 6 atoms in reagents and 6 atoms in products. All atoms are now balanced and the whole equation is fully balanced:
NaOH + H2SO4 = Na2SO4 + H2O is a Double Displacement (Metathesis) reaction where two moles of aqueous Sodium Hydroxide [NaOH] and one mole of aqueous Sulfuric Acid [H 2 SO 4] react to form one mole of aqueous Sodium Sulfate [Na 2 SO 4] and two moles of liquid Water [H 2 O]
2 naoh + 1 h 2 so 4 = 1 na 2 so 4 + 2 h 2 o O is balanced: 6 atoms in reagents and 6 atoms in products. All atoms are now balanced and the whole equation is fully balanced:
Balanced chemical equation: A balanced chemical equation represent the equation in which the number of atom of each element is equal on both the reactant and product side. Given reaction: NaOH Sodium hydroxide + H 2 SO 4 Sulphuric acid → Na 2 SO 4 Sodium sulphate + H 2 O Water
5 sty 2022 · Balanced Chemical Equation – Solution. 2 NaOH + H 2 SO 4 → Na 2 SO 4 + 2 H 2 O. The coefficients show the number of particles (atoms or molecules), and the indices show the number of atoms that make up the molecule. New substances are formed as a result of the rearrangement of the original atoms.
Balancing of chemical equation: Step 1: Write unbalanced equation. NaOH + H SO 2 4 → Na SO 2 4 + H O 2. Step 2: Write down the number of atoms of each element present on both reactant as well as product side. Element Reactant side Product side. Na 1 2. O 5 5. H 3 2. S 1 1. Step 3: Add coefficients to balance the number of atoms at both the sides
