Search results
1 lut 2010 · Here's a query to update a table based on a comparison of another table. If record is not found in tableB, it will update the "active" value to "n". If it's found, will set the value to NULL. UPDATE tableA LEFT JOIN tableB ON tableA.id = tableB.id SET active = IF(tableB.id IS NULL, 'n', NULL)"; Hope this helps someone else.
The format of a DATE value is 'YYYY-MM-DD'. According to standard SQL, no other format is permitted. You should use this format in UPDATE expressions and in the WHERE clause of SELECT statements. For example: SELECT * FROM t1 WHERE date >= '2003-05-05';
23 paź 2021 · The obvious way to fix the error is to change the formatting of your value into the format that MySQL can accept. But rather than editing the value manually, you can use the STR_TO_DATE() function to help you convert the string value into date value.
The MySQL UPDATE Statement. The UPDATE statement is used to modify the existing records in a table. UPDATE Syntax. UPDATE table_name. SET column1 = value1, column2 = value2, ... WHERE condition; Note: Be careful when updating records in a table! Notice the . WHERE clause in the UPDATE statement.
13 paź 2022 · I want to insert into the table with a pair of (id, serial), if neither of id or serial appears in the table. So, I think I might do this: UPDATE device SET updated='<current-time>' WHERE id='<device_id>' OR. serial='<serial_no>' ON UPDATE FAIL INSERT (id,serial,...) VALUES (...)
22 wrz 2023 · SELECT DATE_FORMAT('2021-04-15 14:35:29', '%Y %m %d'); This would throw an error because the date format string is missing its placeholders for hours, minutes, and seconds. A straightforward fix here would be to include those missing elements in your format string. Like so:
mySQL has an IFNULL function, so you could do: UPDATE newspapers SET scan_notes = "data", scan_entered_by = "some_name", scan_modified_date = "current_unix_timestamp" scan_created_date = IFNULL( scan_created_date, "current_unix_timestamp" ) WHERE id = X
