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1 lut 2010 · Here's a query to update a table based on a comparison of another table. If record is not found in tableB, it will update the "active" value to "n". If it's found, will set the value to NULL. UPDATE tableA LEFT JOIN tableB ON tableA.id = tableB.id SET active = IF(tableB.id IS NULL, 'n', NULL)"; Hope this helps someone else.
UPDATE my_table SET comments = GREATEST(CAST(comments AS signed)-3, 0) WHERE something = 123; or the IF() function: UPDATE my_table SET comments = IF(comments>3, comments-3, 0) WHERE something = 123;
In this article, we would like to show you UPDATE query with IF condition in MySQL. Quick solution: UPDATE `table_name` SET `column_name` = IF(condition , if_true, if_false); Practical example. To show UPDATE query with IF condition, we will use the following users table:
16 lis 2021 · I am trying to run an update in a table and I get an "Error Code: 1365. Division by 0". The sql commands I use are these: SET @@autocommit = 0; start transaction; update XE_General. join Locations.
We often use the NULLIF function to prevent the division by zero error in a query. If the MySQL server has ERROR_FOR_DIVISION_BY_ZERO mode enabled, it will issue an error when a division by zero occurred.
The WHERE clause, if given, specifies the conditions that identify which rows to update. With no WHERE clause, all rows are updated. If the ORDER BY clause is specified, the rows are updated in the order that is specified. The LIMIT clause places a limit on the number of rows that can be updated.
The IF statement can have THEN, ELSE, and ELSEIF clauses, and it is terminated with END IF. If a given search_condition evaluates to true, the corresponding THEN or ELSEIF clause statement_list executes. If no search_condition matches, the ELSE clause statement_list executes.
