Search results
1 lut 2010 · Here's a query to update a table based on a comparison of another table. If record is not found in tableB, it will update the "active" value to "n". If it's found, will set the value to NULL. UPDATE tableA LEFT JOIN tableB ON tableA.id = tableB.id SET active = IF(tableB.id IS NULL, 'n', NULL)"; Hope this helps someone else.
In this article, we would like to show you UPDATE query with IF condition in MySQL. Quick solution: UPDATE `table_name` SET `column_name` = IF(condition , if_true, if_false); Practical example. To show UPDATE query with IF condition, we will use the following users table:
Use IF...THEN...ELSEIF...ELSE statement to evaluate multiple conditions sequentially and execute corresponding blocks of statements based on the first true condition, with an optional block of statements to execute if none of the conditions is true.
The WHERE clause, if given, specifies the conditions that identify which rows to update. With no WHERE clause, all rows are updated. If the ORDER BY clause is specified, the rows are updated in the order that is specified. The LIMIT clause places a limit on the number of rows that can be updated.
The IF statement can have THEN, ELSE, and ELSEIF clauses, and it is terminated with END IF. If a given search_condition evaluates to true, the corresponding THEN or ELSEIF clause statement_list executes.
21 sie 2024 · The IF-THEN statement in SQL is used to execute a block of code if a specified condition is true. If the condition evaluates to true, the code within the THEN block is executed. If the condition is false, the block is skipped. Syntax: IF condition THEN. statements; END IF; Parameters Used:
6 paź 2012 · UPDATE `table` SET uid = CASE id WHEN 10 THEN 2952 WHEN 20 THEN 4925 WHEN 30 THEN 1592 END CASE WHERE id IN (10, 20, 30) or the simpler: UPDATE `table` SET uid = ELT(FIELD(id, 10, 20, 30), 2952, 4925, 1592) WHERE id IN (10, 20, 30) As FIELD() returns the index (position) of str in the str1, str2, str3, ... list. Returns 0 if str is not found.
