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1 lut 2010 · Here's a query to update a table based on a comparison of another table. If record is not found in tableB, it will update the "active" value to "n". If it's found, will set the value to NULL. UPDATE tableA LEFT JOIN tableB ON tableA.id = tableB.id SET active = IF(tableB.id IS NULL, 'n', NULL)"; Hope this helps someone else.
In this article, we would like to show you UPDATE query with IF condition in MySQL. Quick solution: UPDATE `table_name` SET `column_name` = IF(condition , if_true, if_false); Practical example. To show UPDATE query with IF condition, we will use the following users table:
The MySQL UPDATE Statement. The UPDATE statement is used to modify the existing records in a table. UPDATE Syntax. UPDATE table_name. SET column1 = value1, column2 = value2, ... WHERE condition; Note: Be careful when updating records in a table! Notice the . WHERE clause in the UPDATE statement.
UPDATE [LOW_PRIORITY] [IGNORE] table_references SET assignment_list [WHERE where_condition] For the single-table syntax, the UPDATE statement updates columns of existing rows in the named table with new values.
Introduction to MySQL UPDATE statement. The UPDATE statement updates data in a table. It allows you to change the values in one or more columns of a single row or multiple rows. The following illustrates the basic syntax of the UPDATE statement: UPDATE [LOW_PRIORITY] [IGNORE] table_name SET column_name1 = expr1, column_name2 = expr2, ... [WHERE ...
21 lut 2013 · MySQL supports IF statement. UPDATE abbonamento. SET punti = IF(tipo = 'punti', punti - 1, punti), bonus = IF(tipo <> 'punti', bonus - 1, bonus) WHERE id = 17. or you can also use CASE. UPDATE abbonamento. SET punti = CASE WHEN tipo = 'punti' THEN punti - 1 ELSE punti END, bonus = CASE WHEN tipo <> 'punti' THEN bonus - 1 ELSE bonus END.
16 kwi 2016 · In MySQL, you can use tuple comparison: WHERE (TestId, TestSubId) IN ((10,25), (11,22)) That looks nice and succinct, although, as ypercubeᵀᴹ mentioned in a comment, it may not work well performance-wise.
