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  1. 1 lut 2010 · Here's a query to update a table based on a comparison of another table. If record is not found in tableB, it will update the "active" value to "n". If it's found, will set the value to NULL. UPDATE tableA LEFT JOIN tableB ON tableA.id = tableB.id SET active = IF(tableB.id IS NULL, 'n', NULL)"; Hope this helps someone else.

  2. In this article, we would like to show you UPDATE query with IF condition in MySQL. Quick solution: UPDATE `table_name` SET `column_name` = IF(condition , if_true, if_false); Practical example. To show UPDATE query with IF condition, we will use the following users table:

  3. The WHERE clause, if given, specifies the conditions that identify which rows to update. With no WHERE clause, all rows are updated. If the ORDER BY clause is specified, the rows are updated in the order that is specified. The LIMIT clause places a limit on the number of rows that can be updated.

  4. The MySQL UPDATE Statement. The UPDATE statement is used to modify the existing records in a table. UPDATE Syntax. UPDATE table_name. SET column1 = value1, column2 = value2, ... WHERE condition; Note: Be careful when updating records in a table! Notice the . WHERE clause in the UPDATE statement.

  5. www.mysqltutorial.org › mysql-stored-procedure › mysql-if-statementMySQL IF Statement - MySQL Tutorial

    The IF statement allows you to evaluate one or more conditions and execute the corresponding code block if the condition is true. The IF statement has three forms: IF...THEN statement: Evaluate one condition and execute a code block if the condition is true.

  6. 16 kwi 2016 · UPDATE Tests AS old INNER JOIN ( SELECT 10 AS TestId, 25 AS TestSubId, 1000 AS TestScore, 2000 AS TestScore2 UNION ALL SELECT 11, 22, 1100, 2100 ) AS new ON old.TestId = new.TestId AND old.TestSubId = new.TestSubId SET old.TestScore = new.TestScore, old.TestScore2 = new.TestScore2 ;

  7. 21 lut 2013 · MySQL supports IF statement. UPDATE abbonamento SET punti = IF(tipo = 'punti', punti - 1, punti), bonus = IF(tipo <> 'punti', bonus - 1, bonus) WHERE id = 17 or you can also use CASE

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