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1 lut 2010 · How do I update a table and set different values upon the condition evaluating to True. For instance : UPDATE Table SET A = '1' IF A > 0 AND A < 1 SET A = '2' IF A > 1 AND A < 2 WHERE...
In this article, we would like to show you UPDATE query with IF condition in MySQL. Quick solution: UPDATE `table_name` SET `column_name` = IF(condition , if_true, if_false); Practical example. To show UPDATE query with IF condition, we will use the following users table:
Summary. Use IF...THEN statement to conditionally execute a block of statements based on the evaluation of a specified condition. Use IF...THEN...ELSE statement to execute a block of statements if a specified condition is true and an alternative block of statements if the condition is false.
For the multiple-table syntax, UPDATE updates rows in each table named in table_references that satisfy the conditions. Each matching row is updated once, even if it matches the conditions multiple times. For multiple-table syntax, ORDER BY and LIMIT cannot be used.
21 lut 2013 · MySQL supports IF statement. UPDATE abbonamento SET punti = IF(tipo = 'punti', punti - 1, punti), bonus = IF(tipo <> 'punti', bonus - 1, bonus) WHERE id = 17 or you can also use CASE
29 kwi 2015 · IF EXISTS (select * from users where username = 'something') THEN. update users set id= 'some' where username = 'something'; ELSE. insert into users (username) values ('something'); END IF; end $$. delimiter ; and call it like this: call select_or_insert();
6 sty 2022 · SELECT case_id, cat, birth, c_type, CASE -- 1st section: WHEN (COUNT(case_id) OVER (PARTITION BY case_id)) = 1 THEN CASE WHEN (DATEDIFF(NOW(), birth) / 365.25) >= 21 THEN 'SINGLE_PERSON' ELSE 'UNKNOWN' END -- 2nd section: WHEN COUNT(case_id) OVER (PARTITION BY case_id) = 2 AND SUM(CASE WHEN cat = 'WIFE' THEN 1 ELSE 0 END) OVER (PARTITION BY ...
