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  1. 11 lis 2015 · You could use the SQL%ROWCOUNT Oracle variable: UPDATE table1 SET field2 = value2, field3 = value3 WHERE field1 = value1; IF (SQL%ROWCOUNT = 0) THEN INSERT INTO table (field1, field2, field3) VALUES (value1, value2, value3); END IF;

  2. 19 mar 2012 · If exists update else insert. A frequent occurrence when writing database procedures is to handle a scenario where given a set of fields, for example a new employee record, update the existing employee record if it exists otherwise create it.

  3. 17 paź 2024 · MySQL provides two ways to insert a row into a table or update the row if it already exists. We can use the INSERT INTO … ON DUPLICATE KEY UPDATE syntax or the REPLACE statement.

  4. This statement is equivalent to: update people_target t set (t.first_name, t.last_name) = ( select s.first_name, s.last_name from people_source s where s.person_id = t.person_id ) where exists ( select null from people_source s where s.person_id = t.person_id).

  5. 29 kwi 2015 · IF EXISTS (select * from users where username = 'something') THEN. update users set id= 'some' where username = 'something'; ELSE. insert into users (username) values ('something'); END IF; end $$. delimiter ; and call it like this: call select_or_insert();

  6. 19 lip 2022 · update customers_dim cd set ( full_name, update_datetime ) = ( select cs.full_name, systimestamp from customers_stage : cs where cs.customer_id = cd.customer_id ) where : exists ( select null from customers_stage ce where : ce.customer_id = cd.customer_id ) Plan hash value: 3378486070

  7. 6 lis 2015 · I have a problem with building a conditional update statement in Oracle. For understandability, I'll simplify the problem and basically my update statement should look like this: UPDATE SAMPLE_TAB1 t . SET t.sample_column1 =NVL(t.sample_column1, **SOME LOGIC**);

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