Search results
1 lut 2010 · Here's a query to update a table based on a comparison of another table. If record is not found in tableB, it will update the "active" value to "n". If it's found, will set the value to NULL. UPDATE tableA LEFT JOIN tableB ON tableA.id = tableB.id SET active = IF(tableB.id IS NULL, 'n', NULL)"; Hope this helps someone else.
11 kwi 2019 · I need to do and IF/THEN statement in mysql based on whether a value exists in a column. If it exists, I need to perform an update on the record and if it does not, then an error should be thrown. ...
In this article, we would like to show you UPDATE query with IF condition in MySQL. Quick solution: UPDATE `table_name` SET `column_name` = IF(condition , if_true, if_false); Practical example. To show UPDATE query with IF condition, we will use the following users table:
29 kwi 2015 · IF EXISTS (select * from users where username = 'something') THEN. update users set id= 'some' where username = 'something'; ELSE. insert into users (username) values ('something'); END IF; end $$. delimiter ; and call it like this: call select_or_insert();
I want to execute an UPDATE clause only in the case a specific row exists. Specifically, if a row in gallery_image exists with a specified position, I want to update all rows with a position higher than that value, flipping the sign of the position value. So this is my try: IF SELECT * FROM gallery_image WHERE position = 'X'.
An UPDATE statement can start with a WITH clause to define common table expressions accessible within the UPDATE. See Section 15.2.20, “WITH (Common Table Expressions)”. Single-table syntax: UPDATE [LOW_PRIORITY] [IGNORE] table_reference . SET assignment_list . [WHERE where_condition] [ORDER BY ...] [LIMIT row_count] value: {expr | DEFAULT}
17 lis 2010 · I want to add a row to a database table, but if a row exists with the same unique key I want to update the row. For example: INSERT INTO table_name (ID, NAME, AGE) VALUES(1, "A", 19); Let’s say the unique key is ID, and in my Database, there is a row with ID = 1.
