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23 cze 2013 · Unfortunately it's not very clear what you want to get in the end, but here is how you could correctly use conditional SET in your UPDATE. UPDATE relation. SET name1 = CASE WHEN userid1 = 3 THEN 'jack' ELSE name1 END, name2 = CASE WHEN userid2 = 3 THEN 'jack' ELSE name2 END. WHERE (userid1 = 3 AND userid2 = 4)
The Update works if I update all fields with the query shown in the top. However when I Leave a textbox empty, then I get an error that the @parameter is missing a value. So trying to find a solution to update only the field where is something written.
11 cze 2020 · One popular implementation of optimistic locking is to keep the old and new values in the application, and upon updating the data use an update like this: Update table Set column1 = :new_column1, column2 = :new_column2, ....
16 kwi 2016 · However, given how the conditions are re-used in your UPDATE statement, you could also take a different approach altogether: represent the affected IDs and the new values as a derived table and use an update with a join:
26 kwi 2017 · What I wrote for the above is this: ALTER TABLE a ADD COLUMN Material INTEGER. UPDATE a SET Material = CASE. WHEN a.Element <= 300000. THEN 80000. ELSE b.Material FROM. a JOIN b ON (a.PCOMP = b.PCOMP AND a.Ply= b.Ply) END. I am using SQLite 3.14.1.
An UPDATE statement can start with a WITH clause to define common table expressions accessible within the UPDATE. See Section 13.2.15, “WITH (Common Table Expressions)”. Single-table syntax: UPDATE [LOW_PRIORITY] [IGNORE] table_reference . SET assignment_list . [WHERE where_condition] [ORDER BY ...] [LIMIT row_count] value: {expr | DEFAULT}
22 gru 2022 · INSERT INTO schema_name.table_name(id, data) VALUES(1, '["3"]') ON DUPLICATE KEY UPDATE data= IF(JSON_CONTAINS(data,'3', '$'), JSON_ARRAY_APPEND(data, '$', '3'), data) It does not insert "3" into data, whether or not it's already present. It doesn't return an error.
