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  1. 13 kwi 2022 · The problem is, if there's a PRIMARY KEY on that table, and the REPLACE INTO does not specify a value for the PRIMARY KEY (for example, it's an AUTO_INCREMENT column), the new row gets a different value, and this may not be what you were looking for in terms of behavior.

  2. In MySQL 8.4, DELAYED is not supported. The server recognizes but ignores the DELAYED keyword, handles the replace as a nondelayed replace, and generates an ER_WARN_LEGACY_SYNTAX_CONVERTED warning: REPLACE DELAYED is no longer supported. The statement was converted to REPLACE.

  3. www.mysqltutorial.org › mysql-basics › mysql-replaceMySQL REPLACE - MySQL Tutorial

    The MySQL REPLACE statement works as follows: Step 1. Insert a new row into the table, if a duplicate key error occurs. Step 2. If the insertion fails due to a duplicate-key error occurs: Delete the conflicting row that causes the duplicate key error from the table. Insert the new row into the table again.

  4. 25 wrz 2019 · The query looks like the following: REPLACE INTO tabB. SELECT * FROM tabA WHERE colA != '--'; Even though the SELECT part is exactly the same, now the query returns the following error: Error: ER_TRUNCATED_WRONG_VALUE: Truncated incorrect DOUBLE value: '--'.

  5. In MySQL 8.1, DELAYED is not supported. The server recognizes but ignores the DELAYED keyword, handles the replace as a nondelayed replace, and generates an ER_WARN_LEGACY_SYNTAX_CONVERTED warning: REPLACE DELAYED is no longer supported.

  6. As with INSERT, if it is not possible to insert the new row into any of these partitions or subpartitions, the REPLACE statement fails with the error Found a row not matching the given partition set. For more information and examples, see Section 24.5, “Partition Selection”.

  7. 7 mar 2024 · MySQL REPLACE Statement. The REPLACE command works similar to INSERT, the only difference being for the matching row, the data for the existing row is replaced and if there’s no existing row (as compared against primary/unique keys) a new row is inserted. Syntax: REPLACE INTO {table_name} [colName1, colName2 ...] VALUES (value_list)

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