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Data from the file, returned as a matrix, multidimensional array, or scalar structure array, depending on the characteristics of the file. Based on the file format of the input file, importdata calls a helper function to read the data.
- Readcell
Import data from a specified sheet and range into a cell...
- Readvars
[Var1,Var2,...,VarN] = readvars(___,Name,Value) creates...
- Load
If you do not specify filename, the load function searches...
- Save
Name of file, specified as a string scalar or character...
- Readmatrix
A = readmatrix(___,Name,Value) creates an array from a file...
- Import Tool
The Import Tool lets you preview and import data from...
- Importdata
Data from the file, returned as a matrix, multidimensional...
- Readcell
MATLAB includes functions tailored to import specific file formats. Consider using format-specific functions when you want to import an entire file or only a portion of a file.
5 lut 2018 · Hello Guys, i want to find out how to determine if an input or selected file from a user is .txt or.mat file. I used this syntax to pick the user input. [filename pathname] = uigetfile({'*.mat'; '*.txt'},'File Selector'); Then i can use it for different functions.
load(filename,"-mat") treats filename as a MAT-file, regardless of the file extension. load( filename ,"-mat", variables ) loads the specified variables from filename . S = load( ___ ) loads data into S , using any of the input argument combinations in previous syntaxes.
There are two major methods of data output, writing to the terminal window, as previously done using disp () function, or, writing to an output file. We have already extensively discussed printing output to the terminal window. Reading from and writing data to file is also easy as we will see here.
29 lis 2014 · If a specific directory is known, one can get the list of files with a proper extension by using: This function returns an array of structures, each structure describes a single file (name, date etc.). From the structures it is easy to extract the file name by a(num_of_file).name.
[filepath,name,ext] = fileparts(filename) returns the path name, file name, and extension for the specified file. fileparts only parses the specified filename. It does not verify that the file exists.
