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24 wrz 2012 · The removal of the element at the 3rd index has already been addressed. However, if you want to remove all occurences of the number '3' from the array 'a', you can use the following code (with and without using the find method).
- Find Array Elements That Meet Conditions
Find Array Elements That Meet Conditions. This example shows...
- Find
To find array elements that meet a condition, use find in...
- Find Array Elements That Meet Conditions
Find Array Elements That Meet Conditions. This example shows how to filter the elements of an array by applying conditions to the array. For instance, you can examine the even elements in a matrix, find the location of all 0s in a multidimensional array, or replace NaN values in data.
To find array elements that meet a condition, use find in conjunction with a relational expression. For example, find(X<5) returns the linear indices to the elements in X that are less than 5 . To directly find the elements in X that satisfy the condition X<5 , use X(X<5) .
17 sty 2021 · In MATLAB, manipulating arrays and matrices can be done much easier than for-loop solutions, in your task, can do find and delete negative value in the array, simply, as follows: Idx_neg = X < 0; % finding X indices corresponding to negative elements X ( Idx_neg ) = []; % removing elements using [] operator Y ( Idx_neg ) = []; % removing ...
7 kwi 2017 · I have a data set (OrbSolPwr) in a 2880 x 1 double array. I only want the first (n) terms. How do I either select the first (n) terms into a new array or delete the (n+1):numel(OrbSolPwr) terms?
12 sty 2020 · I'm trying to find in an array 'done' the position of a value 'next' without the use of a loop. Then, in this array i want to remove from that position found, the existing element. out=find(done==next);
1 paź 2014 · A straightforward way to find and alter matrix elements with a certain property is logical indexing. In your case, if we call your matrix A, you could try something like: >>idx = A>4; //create logical array
