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24 wrz 2012 · Copy. a = [1, 3, 2, 3, 4, 3, 5, 3]; indices_of_3 = find (a == 3); % Find indices of elements equal to 3. removed_values = a (a == 3); % Store the removed values in another variable named 'removed_values'. % Create a vector with zeroes where the number is 3. b = zeros (size (a)); b (a ~= 3) = a (a ~= 3);
- Find and remove a value from an array - MATLAB Answers - MathWorks
I'm trying to find in an array 'done' the position of a...
- Find and remove a value from an array - MATLAB Answers - MathWorks
17 cze 2011 · My testing suggests that Z=Z(Z~=A) is faster than deleting from Z, taking about 82% as long, at least for longer arrays.
12 sty 2020 · I'm trying to find in an array 'done' the position of a value 'next' without the use of a loop. Then, in this array i want to remove from that position found, the existing element. out=find(done==next);
17 sty 2021 · In MATLAB, manipulating arrays and matrices can be done much easier than for-loop solutions, in your task, can do find and delete negative value in the array, simply, as follows: Idx_neg = X < 0; % finding X indices corresponding to negative elements. X ( Idx_neg ) = []; % removing elements using [] operator.
7 kwi 2010 · I have for example a=[1 2 3 4 5 6 7 8 9 10]; and I have to delete each 2 following numbers from 3. like at the end it should be a=[1 4 7 10]; How to do this without a for loop.
7 kwi 2017 · I have a data set (OrbSolPwr) in a 2880 x 1 double array. I only want the first (n) terms. How do I either select the first (n) terms into a new array or delete the (n+1):numel(OrbSolPwr) terms?
Find Array Elements That Meet Conditions. This example shows how to filter the elements of an array by applying conditions to the array. For instance, you can examine the even elements in a matrix, find the location of all 0s in a multidimensional array, or replace NaN values in data.
