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  1. Establish a relationship for how the magnetic field of a solenoid varies with distance and current by using both the Biot-Savart law and Ampère’s law. Establish a relationship for how the magnetic field of a toroid varies with distance and current by using Ampère’s law.

  2. A long straight coil of wire can be used to generate a nearly uniform magnetic field similar to that of a bar magnet. Such coils, called solenoids, have an enormous number of practical applications. The field can be greatly strengthened by the addition of an iron core. Such cores are typical in electromagnets.

  3. www.omnicalculator.com › physics › solenoid-magnetic-fieldSolenoid Magnetic Field Calculator

    To calculate the magnetic field inside a solenoid: Measure the current in the wire, I; Count the number of complete coilings in the solenoid, N; Measure the length of the device, L. Calculate the strength of the magnetic field: B = µ0 · N · I/L; where µ0 is the magnetic permeability of the vacuum.

  4. 12 kwi 2018 · 1. Apply Ampere's law by finding the formula for relating the path of the current and magnetic field: B → • d l →. 2. Find that Ampere's law is proportional to the path and solenoid's length proportionality times the number of turns in the solenoid and the electric current: B l = μ 0 N I l L.

  5. The magnetic field strength inside a solenoid is \[B = \mu_{0}nI \left(inside \quad a \quad solenoid\right), \nonumber\] where \(n\) is the number of loops per unit length of the solenoid. The field inside is very uniform in magnitude and direction.

  6. Establish a relationship for how the magnetic field of a solenoid varies with distance and current by using both the Biot-Savart law and Ampère’s law; Establish a relationship for how the magnetic field of a toroid varies with distance and current by using Ampère’s law

  7. The equation for magnetic field strength 𝐵 at the center of a solenoid using turns per unit of length is 𝐵 = 𝜇 𝑛 𝐼, where 𝑛 is the number of turns per unit of length, 𝐼 is the current of the solenoid, and 𝜇 is the permeability of free space, 4 𝜋 × 1 0 T⋅m/A.

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