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  1. 13 sty 2012 · 1. For "and" logic, you can do nested if conditions, but it's clunky and doesn't help you with the else "unless", or any "or" logic per your question above. – combinatorist. May 3, 2021 at 0:50. 28 Answers. Sorted by: 581. This is possible by 'cheating' with a block helper.

  2. 13 sty 2014 · Handlebars doesn’t support conditional statements, so code like {{#if x > y}} isn’t possible. What do you guys think would be the best solution for it? Handlebars.registerHelper("only_once", function(item, fn){ var buffer; var i = 0; if (i > 0) { buffer = false; } i++; return buffer; });

  3. 21 gru 2021 · You can write any helper and use it in a sub-expression. For example, in checking for initialization of a variable the built-in #if check might not be appropriate as it returns false for empty collections (see Utils.isEmpty). You could write a helper that checks for "undefined" such as: preparationScript.

  4. 10 mar 2024 · This tutorial covers a handlebar if help classes with examples, it also includes how to test conditional block execution in handlebar mustache templates. HandlebarJS provides {{#if}} and {{#unless}} helper provides a helper to conditional test the expression against javascript objects.

  5. 14 mar 2023 · I've built a custom search result page using the PnP Modern Search web parts (v4). I've managed to apply a different file icon based on whether a particular string is in a managed property. I did this using the following code:

  6. Handlebars.registerHelper('ifCond', function(v1, operator, v2, options) {switch (operator) {case '==': return (v1 == v2) ? options.fn(this) : options.inverse(this); break; case '!=': return (v1 != v2) ? options.fn(this) : options.inverse(this); break; case '===': return (v1 === v2) ? options.fn(this) : options.inverse(this); break; case '!==':

  7. I agree with the core argument that Handlebars is bare and you add these things. It means you can add an implementation appropriate for you. Here is a simple version: Handlebars.registerHelper('ifCond', function(v1, v2, options) {if (v1 === v2) {return options.fn(this);} return options.inverse(this);}); BUT.

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