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The period of the graph will be \ (\frac {2 \pi} {B},\) or in this case \ (\frac {2 \pi} {3}\) instead of \ (2 \pi .\) To determine the \ (x\) -values for the maximum, minimum and zero \ (y\) -values, we should examine how these are determined for the standard sine curve.
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Sin2x = 9/25 cos2 x = 16/25 Tan x =9/16 take the 60) 36.86 Sin2(143.14) - Sin(286.28) cos2(143.14) = cos(286.28) Tan2(143.14) - Tan(286.28) Check Solutions: Check Solutions: C *Using a calculator) Since SinX = 3/5, ArcSin of 3/5 (or . The Reference angle X — Also, —.96 .28 -3.42 Since X is in Quad Il, the angle measures 180 — 36.86 = 143.14
