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  1. A pound-foot (lb⋅ft), abbreviated from pound-force foot (lbf · ft), is a unit of torque representing one pound of force acting at a perpendicular distance of one foot from a pivot point. [2] Conversely one foot pound-force (ft · lbf) is the moment about an axis that applies one pound-force at a radius of one foot.

  2. en.wikipedia.org › wiki › TorqueTorque - Wikipedia

    The traditional imperial units for torque are the pound foot (lbf-ft), or, for small values, the pound inch (lbf-in). In the US, torque is most commonly referred to as the foot-pound (denoted as either lb-ft or ft-lb) and the inch-pound (denoted as in-lb).

  3. 8 cze 2024 · Foot-pounds (ft-lb) and pound-feet (lb-ft) are often used interchangeably, but it’s crucial to understand the fundamental distinction between these units to avoid confusion and misinterpretation. ft-lb measures torque or rotational force, while lb-ft measures energy or work done.

  4. transformer. Electric Motors, Generators, and Transformers. As we learned previously, a current-carrying wire in a magnetic field experiences a force—recall F = I ℓ B sin θ . Electric motors, which convert electrical energy into mechanical energy, are the most common application of magnetic force on current-carrying wires.

  5. Describe how the magnitude of a torque depends on the magnitude of the lever arm and the angle the force vector makes with the lever arm; Determine the sign (positive or negative) of a torque using the right-hand rule; Calculate individual torques about a common axis and sum them to find the net torque

  6. Use |\(\vec{\tau}\)| = r \(\perp\) F = rFsin \(\theta\) to find the magnitude and \(\vec{r} = \vec{r} \times \vec{F}\) to determine the sign of the torque. The torque from force 40 N in the first quadrant is given by (4)(40)sin 90° = 160 N • m. The cross product of \(\vec{r}\) and \(\vec{F}\) is out of the page, positive.

  7. phys.libretexts.org › Courses › University_of_California_Davis5.4: Torque - Physics LibreTexts

    21 maj 2023 · Let’s do a sanity check on our definition of torque and its role in the rotational second law. We can do it very simply by choosing a single point mass tied to a string whose other end is held as a fixed pivot (we'll leave gravity out of this).

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