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find equation of plane through point (3,5,1) and contains line x=4-t, y=2t-1, z=-3t. I was able to see how to do this with a parallel and perpendicular plane but I'm not sure how to apply the fact that the plane contains this line to find the plane.
12 sty 2021 · Find an equation of the plane. The plane that passes through the point (3, 5, -1) and contains the line x = 4 - t, y = 2t - 1, z = -3t
Find the equation of the plane containing the point $(1, 3,−2)$ and the line $x = 3 + t$, $y = −2 + 4t$, $z = 1 − 2t$. Don't know where to start?
How to find an equation for the plane that is perpendicular to a line and passes through a point? 1 Find an equation for the plane perpendicular to the line $x=5-3t, y=5t-7, z=-6t$
17 sie 2024 · Example \(\PageIndex{6}\): Writing an Equation for a Plane Given a Point and a Line. Find an equation of the plane that passes through point \((1,4,3)\) and contains the line given by \(x=\dfrac{y−1}{2}=z+1.\)
The equation of the plane passing through three given points A, B, C can be calculated by taking the position vectors of these points as \(\overrightarrow a\), \(\overrightarrow b\), \(\overrightarrow c\) respectively.
It is enough to specify tree non-collinear points in 3D space to construct a plane. Equation, plot, and normal vector of the plane are calculated given x, y, z coordinates of tree points.
