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1 lip 2012 · 1.9 Practice - Age Problems 1. A boy is 10 years older than his brother. In 4 years he will be twice as old as his brother. Find the present age of each. 2. A father is 4 times as old as his son. In 20 years the father will be twice as old as his son. Find the present age of each. 3. Pat is 20 years older than his son James.
Answers - Algebra Word Problems – Lesson 5 - Worksheet 5 - Algebra Word Problems Involving Age Problem 1) Alex is fourteen years old and he is also nine years older than his sister Kristen. How old is Kristen? Solution: Let represent Alex’s age and let represent Kristen’s age. From the problem we can write two equations: =14
The document contains 18 word problems involving algebra and age. The problems ask the reader to determine the ages of various people based on information provided about their ages relative to others and at different points in time.
Problem 1 : Martin is four times as old as his brother Luther at present. After 10 years he will be twice the age of his brother. Find their present ages. Solution : Let x and y be the present ages of Martin and Luther respectively. Given : Martin is four times as old as his brother Luther at present. x = 4y ---- (1)
Learn how to solve age word problems with examples. Understand how to compare two people's ages at different points in time and find relationships using single or multiple variables.
The objective of these problems is usually to find each subject’s current age. Since there can be a lot of information in these problems, a chart can be used to help organize and solve. An example of such a table is below.
On a separate sheet of paper, write your “Let” statement(s) to define the unknown. Solve each problem using an algebraic equation. 1. Twice a number is 500 more than six times the number. What is the number? 2. Three-sevenths of a number is 24. Find the number. 3. What number increased by 1⁄4 of itself is equal to 30? 4.
