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Determine the empirical and molecular formula for chrysotile asbestos. Chrysotile has the following percent composition: 28.03% Mg, 21.60% Si, 1.16% H, and 49.21% O. The molar mass for chrysotile is 520.8 g/mol. Answer.
The first step in determining the formula of a new substance is obtaining its percentage composition. Consider analyzing the composition of C, H, and O in compounds containing these three elements. A sample of known mass of the compound is burnt to get CO2 and H2O.
Empirical Formula Problems – Set I 1. Determine the empirical formula of a compound consisting of : (a) 55.3%K, 14.6%P, and 30.1% O. (K 3 PO 4) (b) 47.3% Cu and 52.7% Cl. (CuCl 2) (c) 52.14%C, 13.13%H, and 34.73% O. (C 2 H 6 O) (d) 40.0%C, 6.73%H and 53.3% O . (CH 2 O) 2. In vanadium oxide, the mole ratio is calculated to be: 2.50 mol O/1 mol V.
solve a system of three linear equations in three variables by graphing, we would have to draw the three planes and then identify the points that lie on all three of them.
Linear Equations A linear equation is an equation involving variables and coe cients, but no products or powers of variables. Some examples: (a)2x + 3y = 6 (b)7u 8v + p 2y + ˇz = 17 (c)75x 1 + 2 19 x 2 + 23x 3 = 3 p ˇ General linear equation: a 1x 1 + a 2x 2 + + a nx n = b (); where a 1;:::;a n;b are real numbers. Lecture 1: Systems of linear ...
Solution. Simply substitute these values of x1, x2, x3, and x4 in each equation. x1 − 2x2 + 3x3 + x4 = + 3s +t = −3 2x1 − x2 + 3x3 − x4 = (t − s 2(t −. 1) − 2(t + s + 2) + 1) − (t + s + 2) + 3s −t = 0. Because both equations are satisfied, it is a solution for all choices of s and t.
Molecular Formula: Example. A compound is found to contain 85.63% C and 14.37% H by mass. In another experiment its molar mass is found to be 56.1 g/mol. What is its molecular formula? CHAPTER 3. Chemical Equations & Reaction Stoichiometry.
