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  1. PROBLEM \(\PageIndex{2}\) Determine the empirical and molecular formula for chrysotile asbestos. Chrysotile has the following percent composition: 28.03% Mg, 21.60% Si, 1.16% H, and 49.21% O. The molar mass for chrysotile is 520.8 g/mol. Answer . Mg 3 Si 2 H 3 O 8 (empirical formula), Mg 6 Si 4 H 6 O 16 (molecular formula)

  2. A 10.00 g sample of vitamin C was analyzed and found to contain 4.092 g of C, 0.458 g of H, and 5.450 g of O. Given that the molar mass of the compound is 176g, determine the molecular formula of vitamin C. (answer: C

  3. The first step in determining the formula of a new substance is obtaining its percentage composition. Consider analyzing the composition of C, H, and O in compounds containing these three elements. A sample of known mass of the compound is burnt to get CO2 and H2O. Masses of CO2 and H2O are related to the mases of C and. H.

  4. Empirical and molecular formula calculations. Let the unknown metal be X. As it is in group 1 the empirical formula must be XCl. There is 47.6% Cl, so the percentage composition of X must be 52.4%. X = 39.02 and the formula is KCl. Pearson Education Australia (a division of Pearson Australia Group Pty Ltd) 2008.

  5. Objectives: • be able to calculate empirical and molecular formulas. Empirical Formula. 1) What is the empirical formula of a compound that contains 0.783g of Carbon, 0.196g of Hydrogen and 0.521g of Oxygen? 2) What is empirical formula of a compound which consists of 89.14% Au and 10.80% of O? 3) What is empirical formula if compound ...

  6. Empirical and Molecular Formula Worksheet ANSWER KEY. Write the empirical formula for the following compounds. A compound with an empirical formula of C2OH4 and a molar mass of 88 grams per mole. What is the molecular formula of this compound? A compound with an empirical formula of C4H4O and a molar mass of 136 grams per mole.

  7. Molecular Formula Example: Calculate the molecular formula of the compound whose molar mass is 60.0 g and the empirical formula is CH4N. CH4N has a MW of: 12 + 1(4) + 14 = 30.0 g.

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