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CuSO4 + Fe = Cu2 + FeSO4 is a Single Displacement (Substitution) reaction where two moles of aqueous Cupric Sulfate [CuSO 4] and two moles of solid Iron [Fe] react to form one mole of solid Dinuclear Copper Ion [Cu 2] and two moles of aqueous Iron(Ii) Sulfate [FeSO 4]
1 CuSO 4 + 1 Fe = 1 FeSO 4 + 1 Cu 2 For each element, we check if the number of atoms is balanced on both sides of the equation. Cu is not balanced: 1 atom in reagents and 2 atoms in products.
1 CuSO 4 + 1 Fe(C 2 H 3 O 2) 2 = 1 Cu(C 2 H 3 O 2) 2 + 1 FeSO 4 Dla każdego elementu sprawdzamy, czy liczba atomów jest zrównoważona po obu stronach równania. Cu jest zrównoważony: 1 atom w odczynnikach i 1 atom w produktach.
Fe + CuSO4 = Fe2(SO4)3 + Cu is a Single Displacement (Substitution) reaction where two moles of solid Iron [Fe] and three moles of aqueous Cupric Sulfate [CuSO 4] react to form one mole of aqueous Ferric Sulfate [Fe 2 (SO 4) 3] and three moles of solid Copper [Cu]
Balance the reaction of CuSO4*5H2O + Fe = Cu + Fe2(SO4)3 + H2O using this chemical equation balancer!
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