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1 CuSO 4 + 1 Fe(C 2 H 3 O 2) 2 = 1 Cu(C 2 H 3 O 2) 2 + 1 FeSO 4 Dla każdego elementu sprawdzamy, czy liczba atomów jest zrównoważona po obu stronach równania. Cu jest zrównoważony: 1 atom w odczynnikach i 1 atom w produktach.
CuSO4 + Fe = Cu2 + FeSO4 is a Single Displacement (Substitution) reaction where two moles of aqueous Cupric Sulfate [CuSO 4] and two moles of solid Iron [Fe] react to form one mole of solid Dinuclear Copper Ion [Cu 2] and two moles of aqueous Iron (Ii) Sulfate [FeSO 4] Show Chemical Structure Image.
1 CuSO 4 + 1 Fe = 1 FeSO 4 + 1 Cu 2 For each element, we check if the number of atoms is balanced on both sides of the equation. Cu is not balanced: 1 atom in reagents and 2 atoms in products.
Word Equation. Copper (Ii) Sulfate Pentahydrate + Iron = Copper + Ferric Sulfate + Water. Three moles of Copper (Ii) Sulfate Pentahydrate [CuSO 4 ·5H 2 O] and two moles of Iron [Fe] react to form three moles of Copper [Cu], one mole of Ferric Sulfate [Fe 2 (SO 4) 3] and fifteen moles of Water [H 2 O] Reactants.
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cuso4+fe=feso4+cu. Have a question about using Wolfram|Alpha? Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals.
1. Identify the reactants and products: Reactants: Iron (Fe) and Copper sulfate (CuSO4) Products: Iron sulfate (FeSO4) and Copper (Cu) Step 2/5 2. Determine the oxidation states of each element: Fe: 0 → +2 Cu: +2 → 0 S: +6 → +4 Step 3/5 3. Balance the equation: Fe + CuSO4 → FeSO4 + Cu Step 4/5 4.
