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To expand an expression using the distributive property, multiply each term inside a set of parentheses by each term outside the parentheses, and then simplify by combining like terms.
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A good method to expand cos(2x) cos (2 x) is by using De Moivre's theorem (r(cos(x)+i ⋅sin(x))n = rn (cos(nx)+i⋅sin(nx))) (r (cos (x) + i ⋅ sin (x)) n = r n (cos (n x) + i ⋅ sin (n x))). When r = 1 r = 1, cos(nx)+i ⋅sin(nx) = (cos(x)+ i⋅sin(x))n cos (n x) + i ⋅ sin (n x) = (cos (x) + i ⋅ sin (x)) n.
Enter a problem... Use the double - angle identity to transform cos(2x) cos (2 x) to 2cos2(x)−1 2 cos 2 (x) - 1. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.
20 maj 2016 · My task is this: Find the taylor-series of $\cos^2x$ and $\sin^2x$. My work so far: We know that $\cos^2x \backslash \sin^2x = \frac{1\pm \cos 2x}{2}$, and the series for $\cos x = \sum_{n=0}^\i...
Use the double - angle identity to transform cos(2x) cos (2 x) to 2cos2(x)−1 2 cos 2 (x) - 1. (2cos2 (x)−1)2 (2 cos 2 (x) - 1) 2. Rewrite (2cos2 (x)−1)2 (2 cos 2 (x) - 1) 2 as (2cos2 (x)−1)(2cos2(x)−1) (2 cos 2 (x) - 1) (2 cos 2 (x) - 1). (2cos2 (x)−1)(2cos2(x)−1) (2 cos 2 (x) - 1) (2 cos 2 (x) - 1)
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How do you use the double angle or half angle formulas to find the exact value of cos2x, when #sinx=(sqrt 5)/3# and #pi/2 <= x <= pi#? How do you use the double angle or half angle formulas to simplify #cos(2a) cos(a) - sin(2a) sin(a)#?
